From: Robert Dober <robert.dober@...>
Date: 2009-07-15T22:06:09+09:00
Subject: Re: Search in string with regular expression

On 7/15/09, Robert Dober <robert.dober@gmail.com> wrote:
> On 7/15/09, Harry Kakueki <list.push@gmail.com> wrote:
>>> Maybe
>>>  str2 = str1.scan( /\bfrog\w*\B/ ).join(" ")
>>> that is if you want to match frog at the start of words only (\b) and
>>> assure charcters of your choice up to the end of the word? As \w might
>>> be a little bit too permissive, in 1.9 you might prefer
>>>   str2 = str1.scan( /\bfrog[[:alpha:]]*\B/ ).join(" ")
>>> and all those nice variations ;)
>>>
>>> HTH
>>> Robert
>>>
>>>
>>>
>> Or maybe, :)
>>
>> str2 = str1.scan( /\bfrog\w*\b/ ).join(" ")
> No it was not a typo, I thought that \B was matching at the end of the
> word, I did not test with a frog at the end.
> I stand corrected \B does not have a special meaning and \b is just a
> word boundary.
I mean \B is not a word boundary and \b is a word boundary and I
wonder WHAT I did test???
Sorry
R.