From: Robert Dober <robert.dober@...>
Date: 2009-07-15T22:03:52+09:00
Subject: Re: Search in string with regular expression

On 7/15/09, Harry Kakueki <list.push@gmail.com> wrote:
>> Maybe
>>  str2 = str1.scan( /\bfrog\w*\B/ ).join(" ")
>> that is if you want to match frog at the start of words only (\b) and
>> assure charcters of your choice up to the end of the word? As \w might
>> be a little bit too permissive, in 1.9 you might prefer
>>   str2 = str1.scan( /\bfrog[[:alpha:]]*\B/ ).join(" ")
>> and all those nice variations ;)
>>
>> HTH
>> Robert
>>
>>
>>
> Or maybe, :)
>
> str2 = str1.scan( /\bfrog\w*\b/ ).join(" ")
No it was not a typo, I thought that \B was matching at the end of the
word, I did not test with a frog at the end.
I stand corrected \B does not have a special meaning and \b is just a
word boundary.

Thx
Robert
> A Look into Japanese Ruby List in English
> http://www.kakueki.com/ruby/list.html
>
>


-- 
Toutes les grandes personnes ont d’abord été des enfants, mais peu
d’entre elles s’en souviennent.

All adults have been children first, but not many remember.

[Antoine de Saint-Exupéry]