From: Vlad Smith Date: 2009-07-02T05:29:04+09:00 Subject: Re: converting the string Greg Willits wrote: > Vlad Smith wrote: >> Hi everybody! I`m sorry for asking a silly question .. i hope you`ll >> find some time to assist >> >> while searching shrough html body i get the string : >> > src='https://sc.omniture.com/sc13_5/reports/chart.php?id=CPRIY_6NvJ_kj7s&s=www461.sj2&type=GIF' >> width=624 height=280 border=0 align=absmiddle >> usemap=#imIY_6NvJ_kj7s> >> >> how can i modify it to get just a plain link without tags and params? : >> https://sc.omniture.com/sc13_5/reports/chart.php?id=CPRIY_6NvJ_kj7s&s=www461.sj2&type=GIF > > You'll have to expand this to take care of all possible scenarios, but > here's an example: > > x = "" > y = x.scan(/src=\"([\S\s]+?)\"/) > > That will return an array, and you'll have to fish the string out of the > array with y[0][0]. > > That works specifically with proper HTML using double quotes where your > examples above used malformed single quotes, but you can either use > multple expressions, or build a more complex one to cover the various > cases of quotes href, src, and other attributes names, etc. > > There's other ways to do it, this is just a small example to give you > some ideas. > > -- gw Thanks! that worked! i also accidently noticed a great feature taken from perl that worked also: x = x = $1 if x =~ /.*(https.*GIF).*/ -- Posted via http://www.ruby-forum.com/.