From: Robert Dober <robert.dober@...>
Date: 2009-06-04T03:18:00+09:00
Subject: Re: return in iterator in lambda

I am not sure what you want to do?

Do you want to return, than I think the above might work with some
tweaking for the non break case, sorry I was lazy.
Or do you just want to break, but than it will not work in Ruby1.9?

Please avoid "for" it confuses me, please use each for my poor brain ;).
Anyway what about this

catch( x ) do
   values.each do
      throw your_value if some_condition
   end
   some more code
 end

Nahh, I guess if you refactor this into methods it will just be
simpler ;) or use Joel's #find if you can, that might give some clean
code too :)

Cheers
Robert

-- 
Toutes les grandes personnes ont d’abord été des enfants, mais peu
d’entre elles s’en souviennent.

All adults have been children first, but not many remember.

[Antoine de Saint-Exupéry]