From: Benjamin Ter kuile <bterkuile@...>
Date: 2009-06-03T06:53:05+09:00
Subject: Re: return in iterator in lambda

Robert Dober wrote:
> On Tue, Jun 2, 2009 at 10:53 PM, Robert Dober <robert.dober@gmail.com> 
> wrote:
>>> �end
>> Well I'll tell you anyway...
>>
>> s/return/break/
>>
> But why did you put something there, now it does not work anymore :(
> Sorry did not see
> 
> lambda f do
>  ...each do
>      break 2
>  end ||
>   something
> end
> 
This will not work for structures like:

data = Array(1..12)
func = lambda do |par|
  answer = 0.0
  for z in data
    answer += Math.log(z)
    return 2e22 if answer > 19
  end
  answer -= data.size*Math.log10(answer)
  answer
end
puts func.call 0.2
puts "after call"

I am converting from fortran, which makes it harder to see the easy
elegant solution :)
The function presented is not the real one, but is more like the one I
am trying to implement.
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