From: Robert Dober <robert.dober@...>
Date: 2009-06-03T05:53:08+09:00
Subject: Re: return in iterator in lambda

On Tue, Jun 2, 2009 at 10:06 PM, Benjamin Ter kuile <bterkuile@gmail.com> wrote:
> I want to create a conditional mathematical function as a lambda
> structure. Therefore it may be the case that inside an iterative loop,
> the result of the function is known and should be returned. By
> implementing this it causes trouble. The test code I created looks like:
>
>
> func = lambda do
>  for z in [1,2,3]
>    return 2
>  end
>  "something"
> end
> puts func.call
> puts "after call"
>
> This results in a LocalJumpError (Ruby 1.8.6 and 1.8.7). In ruby 1.9 it
> works as expected. Is there a proper way of creating a function like
> this in ruby < 1.9?
Yes there is!
Strange you did not ask how though ;)
Well I'll tell you anyway...

s/return/break/

HTH
Robert
>
> Regards,
>
> Benjamin
> --
> Posted via http://www.ruby-forum.com/.
>
>



-- 
Toutes les grandes personnes ont d’abord été des enfants, mais peu
d’entre elles s’en souviennent.

All adults have been children first, but not many remember.

[Antoine de Saint-Exupéry]