From: Boby Selamet Hartono <vecciora@...>
Date: 2009-05-14T16:34:24+09:00
Subject: Re: find previous & next in array

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2009/5/14 Joshua Collins <kidguko@gmail.com>

> Boby had it almost right!
>
> instead of:
>
> a[a.index(:c)+1]
>
> it is:
>
> a[a.index('c')+1]
>
> :-)
>
> On Wed, May 13, 2009 at 11:48 PM, Boby Selamet Hartono
> <vecciora@gmail.com>wrote:
>
> > 2009/5/14 John Griffiths <indiehead@gmail.com>
> >
> > > hi, anyone know how to do this?
> > >
> > > basically i've got an array of items
> > >
> > > a = ['a','b','c','d']
> > >
> > > now given i can find the position of say 'c' using .index('c'), how do
> i
> > > get the positions of the ones previous & next to it.
> > >
> > > a recursive routine would probably do it, but looking for something
> more
> > > flash
> > >
> > > any ideas?
> > > --
> > > Posted via http://www.ruby-forum.com/.
> > >
> > >
> > a[a.index(:c)-1] or a[a.index(:c)+1]?
> >
> > --
> > Tidak ada yang lebih baik dari kembali ke asal
> > Nothing can be better than back to the roots
> >
>

It was a copy from my irb. I'm use symbols  as objects in my array. I've
never use index method but since I figure out that method returns an Integer
I think it would be something like that (thanks to irb). I'm a newbie and
just joining this ML yesterday :-).

-- 
Tidak ada yang lebih baik dari kembali ke asal
Nothing can be better than back to the roots

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