From: Alan Chen <alan@...>
Date: 2002-02-08T09:11:40+09:00
Subject: Re: Why is one slower than the other?

On Fri, Feb 08, 2002 at 06:24:15AM +0900, Alexander Schofield wrote:
> In B you're instantiating a new Regexp on each iteration.
> 
> Kirk Haines wrote:
> > 
> > Program A:
> > 
> > z = 0
> > t = "0123456789abcdefghijklmnopqrstuvwxyz"
> > (0..999999).each {
> >   z += 1 if t =~ /abc/
> > }
> > 
> > Program B:
> > 
> > z = 0
> > t = "0123456789abcdefghijklmnopqrstuvwxyz"
> > rexp = Regexp.new('abc');
> > (0..999999).each {
> >   z += 1 if rexp.match t

you might try replacing this with
     z +=1 if( rexp =~ t )

to get a better comparison

> > }
> > 
> > B has a runtime that is about 1.7 times A.  Why?  This is on Ruby 1.6.6 on
> > a Linux box.
> > 
> > Kirk Haines
> > 
> >   ------------------------------------------------------------------------
> >        Name:
> >        Type: unspecified type (application/octet-stream)
> >    Encoding: base64
> 
> -- 
> Alexander Schofield
> 

-- 
Alan Chen
Digikata LLC
http://digikata.com