From: Kirk Haines <khaines@...>
Date: 2002-02-08T05:13:39+09:00
Subject: Why is one slower than the other?

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Program A:

z = 0
t = "0123456789abcdefghijklmnopqrstuvwxyz"
(0..999999).each {
  z += 1 if t =~ /abc/
}


Program B:

z = 0
t = "0123456789abcdefghijklmnopqrstuvwxyz"
rexp = Regexp.new('abc');
(0..999999).each {
  z += 1 if rexp.match t
}

B has a runtime that is about 1.7 times A.  Why?  This is on Ruby 1.6.6 on
a Linux box.

Kirk Haines




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