From: Ruby Student <ruby.student@...>
Date: 2009-03-20T03:28:14+09:00
Subject: Re: Initializing an NxN array

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On Thu, Mar 19, 2009 at 1:36 PM, Evan Farrar <evanfarrar@gmail.com> wrote:

> Evan Farrar wrote:
> > Since * is defined on array, you can start with a 1x1 array and multiply
> > to the size you need.
> >
> >
> > n = 3;
> > ary = [[0]*n]*n
> >
> > results in:
> > ary => [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
>
> whoops! that has the same problem mentioned above:
> irb(main):026:0> ary[0][0] = :foo; ary
> => [[:foo, 0, 0], [:foo, 0, 0], [:foo, 0, 0]]
>
> I retract!
>  --
> Posted via http://www.ruby-forum.com/.
>
>

Thanks to all, your help is appreicated!

-- 
Ruby Student

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