From: Evan Farrar <evanfarrar@...>
Date: 2009-03-20T02:34:28+09:00
Subject: Re: Initializing an NxN array

Since * is defined on array, you can start with a 1x1 array and multiply 
to the size you need.


n = 3;
ary = [[0]*n]*n

results in:
ary => [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
-- 
Posted via http://www.ruby-forum.com/.