From: Phrogz <phrogz@...>
Date: 2009-03-19T13:47:40+09:00
Subject: Re: how to output two data elements from simple XML

On Mar 18, 5:52 pm, Michael Malone <michael.mal...@tait.co.nz> wrote:
> XPath.match(doc, "//Field FieldId").each do |e|
>    puts "#{e.attribute('Path').to_s.gsub!('/Docs/Animal/', '')}
> #{e.attribute('Attribute')}"
> end
>
> Yes, removing /Docs/Animal/ like that isn't a brilliant idea, but it works.

Perhaps slightly better:
last_path_entry = e.attribute('Path').value[ %r{[^/]+$} ]
or:
last_path_entry = e.attributes['Path'][ %r{[^/]+$} ]
or, if it really can be treated as a file path:
last_path_entry = File.basename( e.attributes['Path'] )