From: AD60 <andredeen@...>
Date: 2009-03-01T06:18:58+09:00
Subject: Newbie question > Hash workings

Hi,

I am puzzled by the workings a the following program. I placed the
output after the corresponding lines. To me it lookes like a sort of
bug in the workings of de p method. Can anybody set me straight?

h = Hash.new([])
h[0] = [1,2,3]
p h                      #> {0=>[1, 2, 3]}
h[0] += [4]
p h                      #> {0=>[1, 2, 3, 4]}
h[1] += [10,11]
p h                      #> {0=>[1, 2, 3, 4], 1=>[10, 11]}
h[1] << 12
p h                     #> {0=>[1, 2, 3, 4], 1=>[10, 11, 12]}
h[2] << 20
p h                     #> {0=>[1, 2, 3, 4], 1=>[10, 11,
12]                          ?
p h[2]                 #>
[20]                                                                   ???
h[2] << 21
p h                     #> {0=>[1, 2, 3, 4], 1=>[10, 11,
12]}                          ?
h[2] += [22]
p h                     #> {0=>[1, 2, 3, 4], 1=>[10, 11, 12], 2=>[20,
21, 22]}  ????????


Grtz. André