From: Bary Buz <sxetikos@...>
Date: 2009-02-25T20:30:14+09:00
Subject: changing the format of a text file

Hello everyone,

i am new to ruby and im having some problems trying to reformat a text
file.

Basically, i have a large log file which is around 200mb in the
following format:
----------------------------------------------------------
1000000             name
Status            :A
Basetype          :2
Version           :1.0
   |
   |
 (more
  fields)
   |
Name              :/file/name/etc
1000001             name
Status            :B
Basetype          :2
Version           :a20
   |
   |
Name              :/file/name/etc
1000002             name
Status            :C
   |

... and so on


so for each 200mb file there are lot of entries.

What i want to do is to open the file, read the data into an array,
reformat the text and save it into another file with the following
output:

id, Status, Basetype, .... , Name
1000000, A, 2, ..... , /file/name/etc
1000001, B, 2, ..... , /file/name/etc

i tried to write a script in ruby to do that task but i dont get any
output so far.

def getfile(file_name)
 entry = []
 IO.foreach(file_name) do |fl|
  if fl.include? 'name'
   entry.push fl.scan(/\d+/)[0]
  elsif fl.strip =~ /\A\d/
  end
 end
 entry
end

def writefile(file, *linedata)
 linedata.each do |line|
  file << line.join(", ") +\n"
  end
end

def readfile(file, outputfile)
 out = File.new(outputfile, "w+")
 info = []

 wline = ['id', 'Status', 'Basetype', .... 'Name']

 IO.foreach(file) { |line|

 if line =~ //
  wline[0]= line.scan(/\d+/)
 elsif line =~ /Status/
  wline[1]= line.split(":")[1].scan(/[a-zA-Z]+/).join("")
 elsif line =~ /Basetype/
  wline[2]= line.split(":")[1].scan(/\d+/).join("")
    |
    |
    |
 wline all fields
    |
 writefile(out, wline)
 end
out.close
end

readfile('filename', 'outputfile')


this is what ive done so far, can someone tell me whats wrong and i dont
get any output at all..

Thanks in advance
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