From: Robert Klemme <shortcutter@...>
Date: 2009-02-24T06:09:28+09:00
Subject: Re: pointer and other questions

On 23.02.2009 21:40, Daniel Schoch wrote:
>> ListElem = Struct.new :prev, :next, :data
>> l1 = ListElem.new
>> li.data = "foo"
>> l2 = ListElem.new
>> l2.prev = l1
>> l1.next = l2
>> l2.data = "bar"
>> p l1
>>
> Ok, that works and solved my problem. Thanks.
> 
> I also found this comment in one of the ruby getting started texts.
>> Ruby variables hold references to objects and the = operator copies
>> references.
> 
> Now what about this ?
> b = 1
> a = b
> b = 2
> Shouldn't 'a' now contain 2 if the above statement is true? Clearly not
> every variable is a reference.

Please think again.  It's the same logic as above.

Cheers

	robert