From: Julian Leviston <julian@...>
Date: 2009-02-16T19:54:33+09:00
Subject: Re: How to do this complicated logic in ruby

Loop the array, changing the values of the hash as you go based on  
some conditional. It's not complex at all. What are you finding  
difficult?

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On 16/02/2009, at 9:00 PM, Valentino Lun <sumwo@yahoo.com> wrote:

> Dear all
>
> I have an array with size around 1000, I want to perform some data
> checking and correction in this array.
>
> For instance, the first record of this array is a hash, as follow
> my_array[0] = {"server"=>"AHN", "hosp"=>"AHN", "loc"=>"PC1",
> "pspec"=>"ANA", "number"=>"1", "pcat"=>"1"}
>
> server  hosp  loc   pspec   pcat
> AHN     AHN   PC1   ANA     1
> PWH     AHN   PC1   ANA     1
> NDH     AHN   PC1   ANA     2     <= This pcat value need update in
> array1
> TMH     AHN   PC1   ANA     2     <= This pcat value need update in
> array1
> .......
> .....
> ...
> (around 1000 records)
>
> When keys hosp, loc, pspec has the same values, their pcat must be
> identical. So, there is problem in the last two records, the key pcat
> should be 1, because the pcat is correct if array["server"] equal to
> array["hosp"].
>
> I cannot figure out the logic to doing this in ruby (even in other
> language). Can someone give me some hints on this? Thanks
>
> Many thanks
> Valentino
> -- 
> Posted via http://www.ruby-forum.com/.
>