From: Phrogz <phrogz@...>
Date: 2009-02-16T09:54:45+09:00
Subject: Re: Iterating a changing Hash under 1.9.1

On Feb 15, 5:07 pm, Charles Oliver Nutter <charles.nut...@sun.com>
wrote:
> Phrogz wrote:
> > I think you're wrong.
> > Initial state: { 0=>0 }
> > First loop: k is 0, a[0] is 1, assign h[1]=>1
> > A brand new key/value has been inserted to the hash this point.
> > If #each then covered the next key/value pair:
> > Second loop: k is 1, a[1] is 2, assign h[2]=>2 (and so on)
>
> There are a maximum of four keys possible and you never remove any. The
> second time through you're reassigning keys that are already there from
> the first time.

I'm confused. As far as I can tell, the hash starts with 1 key, and
ends up with 2. What 'first time' are the keys being set?