From: William James <w_a_x_man@...>
Date: 2009-02-16T05:48:17+09:00
Subject: Re: Multidimensional hash - get all not blank keys

Michael .. wrote:

> Hello.
> 
> I have this Hash.
> 
> result={"1"=>{"6"=>"",
>         "7"=>"",
>         "8"=>"",
>         "1"=>"Value1",
>         "2"=>"",
>         "3"=>"Value2",
>         "4"=>"",
>         "5"=>""},
>       "2"=>{"6"=>"",
>         "7"=>"",
>         "8"=>"Value3",
>         "1"=>"",
>         "2"=>"",
>         "3"=>"",
>         "4"=>"",
>         "5"=>""},
>       "3"=>{"6"=>"",
>         "7"=>"",
>         "8"=>"",
>         "1"=>"",
>         "2"=>"",
>         "3"=>"",
>         "4"=>"",
>         "5"=>""},
>       "4"=>{"6"=>"",
>         "7"=>"",
>         "8"=>"Value4",
>         "1"=>"",
>         "2"=>"Value5",
>         "3"=>"",
>         "4"=>"",
>         "5"=>""}
> }
> 
> 
> Is it possible to get all keys with a the value.
> 1,[1 => Value1]
> 1,[3 => Value2]
> 2,[8 => Value3]
> 4,[8 => Value4]
> 4,[2 => Value5]
> 

result.delete_if{|k,v| {} == v.delete_if{|a,b| b==""}}
p result

{"1"=>{"1"=>"Value1", "3"=>"Value2"}, "2"=>{"8"=>"Value3"},
 "4"=>{"8"=>"Value4", "2"=>"Value5"}}