From: Boris Schmid <borisschmid@...>
Date: 2009-02-09T03:57:43+09:00
Subject: Re: calling random

Am I correct if I remember that using send is quite expensive in 
cpu-time? Especially when I am using it millions of times.. $pop is 
about 5000 hosts large.

10000.times {
    # Events to happen to every host this 0.1 year:
    ["birth","death","infect","evolve"].shuffle.each {|event|

       next if event == "birth" and EVENTS_BIRTH > rand
       next if event == "death" and EVENTS_DEATH > rand
       next if event == "infect" and EVENTS_INFECTION > rand
       next if event == "evolve" and EVENTS_EVOLUTION > rand
       $pop.each {|host|
          next if host == nil
          send(event,host)
       }
   }
}

What I could do is make birth,death,infect and evolve methods of the 
host class, and perhaps use call then. Does that make sense?


David A. Black wrote:
> Hi --
> 
> On Mon, 9 Feb 2009, Boris Schmid wrote:
> 
>> end
>>
>> irb(main):008:0> [f1,f2].each {|fun| [1,2,3,4].each {|val| fun(val)}}
> 
> If f1 and f2 contain actual method objects, you can use call:
> 
>    f1,f2 = method(:f1), method(:f2)
>    [f1,f2].each {|m| [1,2,3,4].each {|e| m.call(e) } }
> 
> Mixing f(unction) and m(ethod) terminology a bit... but that's OK,
> because it will also work if f1 and f2 are Proc objects (which are
> basically anonymous functions.
> 
> If you have strings or symbols, you can use them to get the method
> objects (see above), or you can use send:
> 
>    ["f1", "f2"].each {|m| [1,2,3,4].each {|e| send(m,e)} }
> 
> 
> David
> 
> --
> David A. Black / Ruby Power and Light, LLC
> Ruby/Rails consulting & training: http://www.rubypal.com
> Coming in 2009: The Well-Grounded Rubyist (http://manning.com/black2)
> 
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