From: Albert Schlef <albertschlef@...>
Date: 2009-01-29T11:11:44+09:00
Subject: Re: Bitwise question

Pascal J. Bourguignon wrote:
> Albert Schlef <albertschlef@gmail.com> writes:
> > One, you need to do (1 << (b-1)). 
> Bit 0 is the first bit.  2^0 = 1

I stand corrected.

> > Two, if you pass [] as the bits, the 
> > result will be 'true'.
>
> Which is of course the correct answer.
> All the bits in the empty set are in any bitfield.
> There is no bit in the empty set hat are not in a given bitfield.

All right, all right, you win ;-)  I now see that [].all? too returns 
'true'.

(So my attempt at dissuading you from using parenthesis failed 
miserably. Say, won't you consider dropping them for humanitarian 
reasons?)
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