From: Jason Lillywhite <jason.lillywhite@...>
Date: 2009-01-29T00:49:27+09:00
Subject: function inside a function

I have a question about the timing of function evaluations in this case:

def function_a(x = 1)
  x**2 + x
end

def function_b(any_function)
  y = 4 + 5 #this would actually be more complex
  function_a(y)
end

puts function_b(function_a)

I found that function_a(x = 1) is evaluated first, then
function_b(function_a). I found that 'def function_a(x = nil) returns an
error. Why does function_a need to be evaluated before it is called as
an argument in function_b?

PS - the reason I am writing things this way is to make function_b
accept any function (within reason).
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