From: Stefan Kanev <stefan.kanev@...>
Date: 2009-01-27T23:30:04+09:00
Subject: Re: How can I get the arguments passed to the caller.

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Thanks for the advice. I would have never had thought of something as
straightforward as evaling 'local_variables' in the binding. Unfortunatelly,
I believe that this doesn't yield the arguments if they are not named.

I'm actually trying, out of curiosity, to implement a very straightforward
idea:

  %w{more chunky bacon}.each { puts it.length }

Like, have *it* to actually be the 'implicit blog argument', not unlike
perl's $_. Again, I'm doing that out of curiosity. Any ideas how I can
accomplish it without touching the interpreter's C code? :)

On Mon, Jan 26, 2009 at 10:35 AM, Brian Candler <b.candler@pobox.com> wrote:

> James Coglan wrote:
> >>  first_arg = ....
> >>  $stuff << first_arg
> >> end
> >>
> >> bar(42)
> >>
> >> # By this point, $stuff would be [42]
> >
> >
> >
> > I think the closest you're going to get is for the calling function to
> > pass
> > its binding so that foo can read from it:
>
> In which case, it might as well just pass its args instead :-)
>
> There is the Binding.of_caller hack which you can find through a google
> search.
>
> Maybe you could combine this with Kernel#local_variables or
> Binding#local_variables to do what you want? That's what debug.rb does
>
>    when /^\s*l(?:ocal)?\s*$/
>      var_list(eval("local_variables", binding), binding)
>
> and just use eval to read them:
>
>  def var_list(ary, binding)
>    ary.sort!
>    for v in ary
>      stdout.printf "  %s => %s\n", v, eval(v, binding).inspect
>    end
>  end
> --
> Posted via http://www.ruby-forum.com/.
>
>

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