From: Andy Cooper <acooper@...>
Date: 2009-01-14T07:30:31+09:00
Subject: Re: Returning a duplicate from an Array

> Andy Cooper wrote:
> > 
> > Without really looking into it a quick and dirty way would 
> be to just
> > subtract the results of .uniq from the initial array.
> > 
> > Andy Cooper.
> 
> Thanks for the quick reply! However, after trying it, I found that 
> subtracting an array from an array will delete each instance of an 
> element, leaving me with a blank array, IE:
> 
> [ 1, 1, 2, 2, 3, 3, 4, 5 ] - [ 1, 2, 4 ]  #=>  [ 3, 3, 5 ]
> 
> Any other ideas?
> 
> Thanks again,
>  - Jeff Miller
> -- 

Yeah, I am winning the typing contest today.

>   def dups(ary=[])
>     uniq=ary.uniq
>     ary.reject{|z| if(uniq.include?(z));q-=[z];true;end}
>   end

Should actually be

   def dups(ary=[])
     uniq=ary.uniq
     ary.reject{|z| if(uniq.include?(z));uniq-=[z];true;end}
   end

Made a mistake when I made q make more sense aparently.

Andy Cooper