From: Adam Kittelson <adam.kittelson@...>
Date: 2009-01-10T07:43:07+09:00
Subject: Re: value of an expression?

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 s = "surprising" if (1+1 != 2)

There are two expressions here, and the if is acting as a modifier. The
first expression (s = "surprising") is only evaluated if the second
expression (1 + 1 != 2) evaluates as true.

It is the equivalent of:

if (1 + 1 != 2)
     s = "surprising"
end

So s = "surprising" is never evaluated, and s continues to equal "test".

Googling "ruby if modifier" should turn up some results.

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