From: Kedar Mhaswade <kedar.mhaswade@...>
Date: 2009-01-10T07:29:32+09:00
Subject: value of an expression?

Sorry if this is asked before and I could not find its answer. Take a
look at the following:
------------------------------------------
1 #!/usr/bin/ruby
2 s="test"
3 puts s
4 s="surprising" if (1+1 != 2)
5 puts s
------------------------------------------
which produces the output:
test
test

but I expected it to output:
test
nil

since I thought the expression in line number 5 ("surprising" if (1+1 !=
2)) should evaluate to nil and hence s should be assigned nil.

So, my question is:
- Why?
- What should I read to understand this better?

Thank you!
-Kedar
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