From: Rob Biedenharn <Rob@...>
Date: 2009-01-05T05:46:17+09:00
Subject: Re: Finding filename from a URL


On Jan 4, 2009, at 1:04 PM, Robert Klemme wrote:

> On 04.01.2009 17:29, Sam Fent wrote:
>> This is just a basic parsing question, really. I'm trying to work out
>> how I would process a URL such as
>> "http://www.example.com/x/y/z/myfile.txt" and get back the filename
>> "myfile". Basically the pattern is to get the past part of the string
>> after the final /, and then strip off the filetype.
>
> IMHO it is not a good idea to use a File method for URL's because  
> File.basename has different criteria
>
> irb(main):003:0> File.basename 'http://test.com/aaa\\bbb.txt'
> => "bbb.txt"
>
> Although I am not sure whether a backslash is allowed there, this is  
> what I'd do:
>
> irb(main):001:0> url = 'http://www.example.com/x/y/z/myfile.txt'
> => "http://www.example.com/x/y/z/myfile.txt"
> irb(main):002:0> name = url[%r{[^/]+\z}]
> => "myfile.txt"
>
> Kind regards
>
> 	robert
>


Rather than jump to a Regexp, just use the right tool for the job.

irb> require 'uri'
=> true
irb> u=URI.parse 'http://www.example.com/x/y/z/myfile.txt'
=> #<URI::HTTP:0x1cac14 URL:http://www.example.com/x/y/z/myfile.txt>
irb> u.path
=> "/x/y/z/myfile.txt"
irb> File.basename u.path, '.txt'
=> "myfile"

-Rob

Rob Biedenharn		http://agileconsultingllc.com
Rob@AgileConsultingLLC.com