From: Robert Klemme Date: 2009-01-05T03:04:06+09:00 Subject: Re: Finding filename from a URL On 04.01.2009 17:29, Sam Fent wrote: > This is just a basic parsing question, really. I'm trying to work out > how I would process a URL such as > "http://www.example.com/x/y/z/myfile.txt" and get back the filename > "myfile". Basically the pattern is to get the past part of the string > after the final /, and then strip off the filetype. IMHO it is not a good idea to use a File method for URL's because File.basename has different criteria irb(main):003:0> File.basename 'http://test.com/aaa\\bbb.txt' => "bbb.txt" Although I am not sure whether a backslash is allowed there, this is what I'd do: irb(main):001:0> url = 'http://www.example.com/x/y/z/myfile.txt' => "http://www.example.com/x/y/z/myfile.txt" irb(main):002:0> name = url[%r{[^/]+\z}] => "myfile.txt" Kind regards robert