From: prasad <gdprasad@...>
Date: 2008-12-01T21:36:54+09:00
Subject: Re: Control Structures

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sorry error: first line should be

while (arr = Array.new(4){rand 4}) != [0,1,2,3]

Prasad



On Mon, Dec 1, 2008 at 6:08 PM, prasad <gdprasad@gmail.com> wrote:

> See if this satisfies you:
>
> while (arr = Array.new(4){rand 4}) != [0,1,2,4]
>   p arr
> end
> p arr
>
> best wishes,
> Prasad
>
>
>
> On Mon, Dec 1, 2008 at 5:07 PM, Trent Jones <1337indi@gmail.com> wrote:
>
>> G'day all, I'm new to Ruby, been studying Software Engineering at
>> university and they have been teaching in Java.
>>
>> As such, I'm trying to learn as few of the basics by going through and
>> comverting smoe of the programs I made into Ruby. At the moment, I'm
>> struggling a bit with the control structures, if-then-else is fine,
>> switch/case is fine. I'm just a little confused about the for and
>> while/dowhile loops.
>>
>> I'm trying to make a "infinite monkeys" simulation, i.e. initiate an
>> array of 'x' length and then fill it with random numbers, then check to
>> see if those numbers are in order, if not, repeat the process. More or
>> less anyway.
>>
>> At the moment I'm using this loop to fill the array:
>>  for num in (0..Integer(a))
>>    monkey[num]=Integer(rand*5+1)
>>  end
>> variable 'a' is input by the user to determine how big a sequence, i.e.
>> 5 numbers in a row.
>>
>> Is this the easiest way of doing things?
>> And then I could use a similar loop to go through and check to see if
>> each number is in order, but again, is there a simpler way to check?
>>
>> Thanks in advance.
>> TJ
>> --
>> Posted via http://www.ruby-forum.com/.
>>
>>
>

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