From: "Daniel Malcolm Webb [dbw]" <dbw@...>
Date: 2008-12-01T21:02:16+09:00
Subject: Re: Control Structures

Hi Jakub,

What would be the quickest way of doing it? (in terms of time and memory?)

Thanks,
Dan

-----Original Message-----
From: Jakub Pavlík jn. [mailto:severus@post.cz] 
Sent: 01 December 2008 11:53
To: ruby-talk ML
Subject: Re: Control Structures

> G'day all, I'm new to Ruby, been studying Software Engineering at
> university and they have been teaching in Java.
> 
> As such, I'm trying to learn as few of the basics by going through and
> comverting smoe of the programs I made into Ruby. At the moment, I'm
> struggling a bit with the control structures, if-then-else is fine,
> switch/case is fine. I'm just a little confused about the for and
> while/dowhile loops.
> 
> I'm trying to make a "infinite monkeys" simulation, i.e. initiate an
> array of 'x' length and then fill it with random numbers, then check to
> see if those numbers are in order, if not, repeat the process. More or
> less anyway.
> 
> At the moment I'm using this loop to fill the array:
>   for num in (0..Integer(a))
>     monkey[num]=Integer(rand*5+1)
>   end
> variable 'a' is input by the user to determine how big a sequence, i.e.
> 5 numbers in a row.
> 
> Is this the easiest way of doing things?
> And then I could use a similar loop to go through and check to see if
> each number is in order, but again, is there a simpler way to check?
> 
> Thanks in advance.
> TJ
> -- 
> Posted via http://www.ruby-forum.com/.

monkey = []
a = gets

begin
  0.upto(a.to_i) do |num|
    monkey.push((rand*5+1).to_i)
  end
end while a.sort != a

(Of course it is not the most time- and memory- effective way...)

Jakub Pavlik
-- 
Zatímco velbloud dvouhrbý má hrby dva, Dromedár má jen jeden.