From: Hai anh Le <lhanh@...>
Date: 2008-11-28T00:24:42+09:00
Subject: Re: reg exp

Brian Candler wrote:
> Hai anh Le wrote:
>> Hi every body. I'm a newbie in Ruby and have problem with reg exp.
>> 
>> In one string as example "The device 13c include something as in Fig. 2a
>> and 3b", I want to detect some numbers have style "13c" and ignore
>> others number have style "2a and 3b"
>> 
>> I use /(\d+[a-z]*)( [^a][^n][^d] )(\d)+[a-z]*/ but it not ok. Can
>> someone help me plz?
> 
> Tricky. I suggest:
> 
>   str.scan(/\d+[a-z]?(?: and \d+[a-z]?)?/).reject { |e| /and/ =~ e }
> 
> I thought about lookahead assertions, e.g. (?! and \d+), but since these 
> don't consume characters the 3b is likely to be matched later as a 
> standalone number.
> 
> Details at http://www.ruby-doc.org/docs/ProgrammingRuby/ - click on "The 
> Ruby Language" in the contents, and scroll down to Extensions.

Hi Brian!

I have another example as:

"The coefficients are then mixed with the data from mixer 51xy, so that 
the recording equipment 14abc stores the six channel data stream, the 
scripting data 26aa and 27ac"

My purpose is to find the position of number have style "123abc", after 
that I get the string from begin to that position like "The coefficients 
are then mixed with the data from mixer 51xy,"
Then I will continued search...

My code like

while string.size do
if string=~ /.../ then
  temp_string = $` + $&
  string.gsub!(temp_string, "")
else
  break
end


So that what I need is $& = "123abc" and not = "123abc and 123abc"





-- 
Posted via http://www.ruby-forum.com/.