From: "David A. Black" <dblack@...>
Date: 2008-11-27T18:32:08+09:00
Subject: Re: creating a dynamic hash

Hi --

On Thu, 27 Nov 2008, Heesob Park wrote:

> 2008/11/27 Sijo Kg <sijo@maxxion.com>:
>> Hi
>>    I could solve the problem like
>> hashes = []
>>          for i in 0..elapsedtime.length-1
>>             hashes[i] = {:bevel => 'bevel1',:value => 5}
>>          end
>> return hashes
>>
> You can do it like this
>
> hashes = [{:bevel => 'bevel1',:value => 5}] * (elapsedtime.length-1)

That's not the same, because you get the same hash n times, instead of
n hashes once each.

hashes = [{:x => 1, :y => 2}] * 3
hashes[0].delete(:x)
p hashes        # [{:y=>2}, {:y=>2}, {:y=>2}]


David

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