From: "Shot (Piotr Szotkowski)" <shot@...>
Date: 2008-11-23T10:18:10+09:00
Subject: Printing right arrow vs. a sane progressbar library

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I want to track the progress of a set of (forkoff=E2=80=99d) processes in
a simple way. What I have in mind is a line of dots equal in length
to the number of processes, and once a process number X finishes,
it prints \r, then advances X characters to the right and prints o
=E2=80=93 so after three of eight processes finish, it could look like ..o.=
=2Eoo.

The closest I got is the below (in one line, so easily pastable to IRB):

print '.' * 25; (0...25).sort_by{rand}.each { |n| print "\r"; print "\c[[C"=
 * n; print 'o'; sleep 0.5 }; print "\n"

It seems to work in IRB and in a script (after $stdout.sync =3D true),
unless the number of processes is larger than the terminal window=E2=80=99s
width.

Is this a sane method of doing what I want to do, or does
it just =E2=80=98happens to work=E2=80=99 in GNOME Terminal on my Ubuntu?

Is there a saner way to advance by a char than printing the right arrow?

On a similar note: Is there a simple progressbar library for Ruby
(ideally if itcan be somehow used with forkoff=E2=80=99d processes, but I=
=E2=80=99m
aware it=E2=80=99d require some kind of passing of state to the outside of =
the
block)?

Is there anything else than Ruby/ProgressBar=C2=B9 (say, in a gem=E2=80=A6)?

=C2=B9 http://0xcc.net/ruby-progressbar/

(I=E2=80=99m aware the above is prone to a race condition if two processes
finish at the same time and the second one of them prints its \r
before the first one prints its o, but let=E2=80=99s disregard this for now=
=2E)

-- Shot
--=20
If I was to use Bugzilla when I was a tester, I'd quit
and become a gardener.      -- a Syllable OS developer

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