From: "Einar Magnús Boson" <einarmagnus@...>
Date: 2008-11-20T01:06:38+09:00
Subject: Re: build hash by iterating


On 19.11.2008, at 15:31 , Jason Lillywhite wrote:

> I am building a hash this way:
>
> h = {}
> i = 0
> j = 24
>
> while i < 15 do
>  h[i] = j
>  i += 1
>  j += 6
> end
>
> => {5=>54, 11=>90, 0=>24, 6=>60, 12=>96, 1=>30, 7=>66, 13=>102, 2=>36,
> 8=>72, 14=>108, 3=>42, 9=>78, 4=>48, 10=>84}
>
> Just what I need, but doesn't seem very Ruby-friendly
>
> And if I want to change each hash value from fixnum to string, how  
> would
> that be done?
>
> this is not working:  new_hash = h.each_key {|k| h[k].to_s}
>
> thank you!
> -- 
> Posted via http://www.ruby-forum.com/.
>


h = (0...15).inject({}) {|h, i| h[i] = (24+i*6).to_s; h}
p h

# but this hash makes no sense.
# just do

h = Array.new(15) {|i| (24+i*6).to_s}
p h

#then you can index the array:
p h[11]

p h[5]


# >> {5=>"54", 11=>"90", 0=>"24", 6=>"60", 12=>"96", 1=>"30", 7=>"66",  
13=>"102", 2=>"36", 8=>"72", 14=>"108", 3=>"42", 9=>"78", 4=>"48",  
10=>"84"}
# >> ["24", "30", "36", "42", "48", "54", "60", "66", "72", "78",  
"84", "90", "96", "102", "108"]
# >> "90"
# >> "54"


einarmagnus