From: "ara.t.howard" <ara.t.howard@...>
Date: 2008-11-20T00:51:14+09:00
Subject: Re: build hash by iterating


On Nov 19, 2008, at 8:31 AM, Jason Lillywhite wrote:

> I am building a hash this way:
>
> h = {}
> i = 0
> j = 24
>
> while i < 15 do
>  h[i] = j
>  i += 1
>  j += 6
> end
>
> => {5=>54, 11=>90, 0=>24, 6=>60, 12=>96, 1=>30, 7=>66, 13=>102, 2=>36,
> 8=>72, 14=>108, 3=>42, 9=>78, 4=>48, 10=>84}
>
> Just what I need, but doesn't seem very Ruby-friendly
>
> And if I want to change each hash value from fixnum to string, how  
> would
> that be done?
>
> this is not working:  new_hash = h.each_key {|k| h[k].to_s}
>
> thank you!
> -- 
> Posted via http://www.ruby-forum.com/.
>



i might do


cfp:~ > cat a.rb
h = {} and 15.times{|i| h[i] = (24 + (i * 6))}

p h.sort

p({5=>54, 11=>90, 0=>24, 6=>60, 12=>96, 1=>30, 7=>66, 13=>102, 2=>36,  
8=>72, 14=>108, 3=>42, 9=>78, 4=>48, 10=>84}.sort)



cfp:~ > ruby a.rb
[[0, 24], [1, 30], [2, 36], [3, 42], [4, 48], [5, 54], [6, 60], [7,  
66], [8, 72], [9, 78], [10, 84], [11, 90], [12, 96], [13, 102], [14,  
108]]
[[0, 24], [1, 30], [2, 36], [3, 42], [4, 48], [5, 54], [6, 60], [7,  
66], [8, 72], [9, 78], [10, 84], [11, 90], [12, 96], [13, 102], [14,  
108]]

a @ http://codeforpeople.com/
--
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better. simply reflect on that.
h.h. the 14th dalai lama