From: Florian Gilcher <flo@...>
Date: 2008-11-19T19:58:07+09:00
Subject: Re: RegExp problem

Actually the correct regexp is:

delimiter = Regexp.escape(delimiter)
/#{delimiter}[^#{delimiter}]*#{delimiter}/

Read: The delimiter - an unspecified number of non-delimiter- 
characters - the delimiter.

Otherwise, you too heavily rely on the behaviour of the library, when  
it coms to the dot.

Regards,
Florian Gilcher

On Nov 19, 2008, at 11:17 AM, Jesús Gabriel y Galán wrote:

> On Wed, Nov 19, 2008 at 10:55 AM, Jf Rejza <jfferriere@gmail.com>  
> wrote:
>> Hy,
>>
>> I would like to know how to extract a string delimited by too  
>> identical
>> characters from an another string(of any length).
>>
>> ex string="rzerze@foo@rezrzgrtez" how to get (or match) the foo  
>> string
>
> irb(main):016:0> string="rzerze@foo@rezrzgrtez"
> => "rzerze@foo@rezrzgrtez"
> irb(main):017:0> (string.match /@(.*?)@/)[1]
> => "foo"
>
> I don't quite understand the rest of your requirement. You mean  
> delimited
> by a string, i.e. the @ above is a variable, or by two of any  
> character present
> in a string? If it's the former:
>
> irb(main):018:0> delimiter = "@"
> => "@"
> irb(main):019:0> (string.match /#{delimiter}(.*?)#{delimiter}/)[1]
> => "foo"
>
> if it's the latter, something like this might help:
>
> irb(main):024:0> re = Regexp.new("([#{delimiter}])(.*)?\\1")
> => /([@abcde])(.*)?\1/
> irb(main):025:0> string.match(re)[2]
> => "rze@foo@rezrzgrt"
>
> It found the first 'e' as the delimiter, don't know why it took the
> last 'e' as the other part of the delimiter, since I used a non-greedy
> group for the middle part. Any ideas, someone?
>
> Hope this helps,
>
> Jesus.
>