From: James Gray <james@...>
Date: 2008-11-16T14:13:31+09:00
Subject: Re: IO#lineno= doesn't work the way I expected

On Nov 15, 2008, at 7:38 PM, Chad Perrin wrote:

> On Sun, Nov 16, 2008 at 09:51:16AM +0900, Jens Wille wrote:
>>
>
>> not sure what tim was suggesting, but this will work:
>>
>>  in_fh = File.open(infile, 'r')
>>  out_fh = File.open(outfile, 'w')
>>
>>  # ignore first line
>>  in_fh.gets
>>
>>  in_fh.each_line do |l|
>>    out_fh << l
>>  end
>>
>> ok, it's not pretty, but not *that* ugly either, is it? ;-)
>
> Actually, that looks pretty good, all things considered.  I didn't
> realize the IO#gets would increment the line number of the file so the
> each_line iterator would start on the second line.  If that's how it
> works, I'm home free.  Thank you for your help.
>
> I'll go test this now to make sure it works.

It works fine and, to be clear, it has nothing to do with line  
numbers.  gets() reads forward to a newline character, advancing the  
file pointer (represented by tell()/pos()) normally.  each() works the  
same way, beginning at the current file pointer location.  I think  
this is pretty standard I/O streaming logic in any language.

James Edward Gray II