From: Tarek Other <cashew250@...>
Date: 2008-11-13T15:59:44+09:00
Subject: Re: Issue with block and getting to local variables

Hi and thanks to all for the help.

Can someone explain why this doesnt work

def foo
  x = 5
  yield
end

foo{puts x}


Q1) The only way to get it to work is to pass x into it when calling the 
yield. Why is that, according to above the block does/should have access 
to it because it is being called withing the scope of the variable

Q2) This is ultimately what I want to do (psuedo code below):

def my_function(&block)
  x = 5
  s = 15
  block.call
end

my_block = lamda{ puts "#{s+x}" }
my_function(&my_block)

But it complains about not knowing what s and x are, ie out of scope. 
Why and how can this be resolved?

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