From: Peter Szinek <peter@...>
Date: 2008-11-11T22:50:14+09:00
Subject: Re: using regular expressions...


On 2008.11.11., at 14:22, soldier.coder wrote:

> I have the following code:
>
> require 'open-uri'
> def scrape_table(html)
>  %r{</thead.*?>(.*?)</table>}m =~html
>  $1
> end
>
> def scrape_case(a_line)
>  %r{(<a\s.*?\d{6}-\d{2}'>\d{6}-\d{2}<\/a>)}m =~ a_line
>  $1
> end

>  Is there any way I can grab all those links into an array?

Sure - String#scan is your friend:

def scrape_case(a_line)
   a_line.scan(/<a\s.*?\d{6}-\d{2}'>\d{6}-\d{2}<\/a>/)
end

ex:

 >> "<a href='123456-78'>123456-78</a> here is another: <a  
href='111111-99'>111111-99</a>".scan(/<a\s.*?\d{6}-\d{2}'>\d{6}-\d{2}< 
\/a>/)
=> ["<a href='123456-78'>123456-78</a>", "<a  
href='111111-99'>111111-99</a>"]


HTH,
Peter