From: Yuh-Ruey Chen <maian330@...>
Date: 2008-11-02T08:08:48+09:00
Subject: Re: How to access to local variables in enclosing scopes?

On Nov 1, 5:26 pm, "ara.t.howard" <ara.t.how...@gmail.com> wrote:
> On Nov 1, 2008, at 4:08 PM, Yuh-Ruey Chen wrote:
>
> > I'm not following you. Ruby uses lexical scope? AFAIK, it only does
> > that constants and not local variables.
>
> if you are having a hard time doing something perhaps you could show
> it?  one thing ruby does well is get things done with a happy medium
> of abstraction.  unless something stands in the way of getting things
> done simply it's sort of a non-issue don't you think?
>
> cheers.
>
> a @http://codeforpeople.com/
> --
> we can deny everything, except that we have the possibility of being
> better. simply reflect on that.
> h.h. the 14th dalai lama

I have already posted an example:

def foo
        a = 10
        def bar
                # should somehow be able to access a
        end
        bar
end
foo
# here, we should not be able to access foo's a, but if there is
another a in scope, we can access that

Of course, afterwards I found out that Ruby doesn't really have nested
procedures, even if it tricks you into thinking that has them. So it's
kinda a moot point now.