From: Rob Biedenharn <Rob@...>
Date: 2008-10-31T10:23:17+09:00
Subject: Re: how to sort this array

On Oct 30, 2008, at 6:34 PM, Simon Krahnke wrote:
> * Li Chen <chen_li3@yahoo.com> (22:14) schrieb:
>
>> files=[
>>  "c:/ruby/self/2004/20.txt",
>>  "c:/ruby/self/2004/3.txt",
>>  "c:/ruby/self/2004/2.txt",
>>  "c:/ruby/self/2004/10.txt",
>>  "c:/ruby/self/2004/1.txt"
>> ]
>>
>> expected results:
>> [
>> "c:/ruby/self/2004/1.txt",
>> "c:/ruby/self/2004/2.txt",
>> "c:/ruby/self/2004/3.txt",
>> "c:/ruby/self/2004/10.txt",
>> "c:/ruby/self/2004/20.txt",
>> ]
>
> files.sort_by { | fn | fn.match(/(\d+)\.txt$/)[1].to_i }
>
> mfg,                   simon .... hth


Since #to_i will stop at a non-digit, you could get simpler:

files.sort_by {|fn| fn[%r{.*/([^/]+)},1].to_i }

I tend to use %r{ } when the Regexp deals with / characters.

-Rob

Rob Biedenharn		http://agileconsultingllc.com
Rob@AgileConsultingLLC.com