From: Brian Candler <b.candler@...>
Date: 2008-10-18T00:31:55+09:00
Subject: Re: RSA public_encrypt bug?

Brian Candler wrote:
> I think I was using integers, so perhaps f.gets.to_i ?
> 
> Also, you could try writing out a PEM, and then using that at the 
> openssl command line, to check that your key is actually valid.

Here's the rest of the code which I used (in 2004 :-) to do this for a 
private key - however I think if you just remove the p and q bits then 
you should get a public key instead.

require 'openssl'
require 'rsa_new'

# Input: a large number n
#        an exponent
#        factor p of n
#        factor q of n  (n = p * q)
# Output: a PEM-encoded private key

n = gets.to_i
e = gets.to_i
p = gets.to_i
q = gets.to_i
p,q = q,p if p < q

puts OpenSSL::PKey::RSA.new_from_parameters(n, e, nil, p, q)
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