From: "David A. Black" <dblack@...>
Date: 2008-10-08T10:19:02+09:00
Subject: Re: Looking for more Ruby-like way to create an array

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Hi --

On Wed, 8 Oct 2008, William James wrote:

> On Oct 7, 4:33=A0pm, Steve Nicholson <sst...@mac.com> wrote:
>> I'm creating an array that is the result of the members of another array
>> each multiplied by 100. Here's what I have:
>>
>> =A0 converted_array =3D []
>> =A0 original_array.each {|line| converted_array << line.to_f * 100}
>>
>> This works, but I'm wondering if there is a more idiomatically "Ruby"
>> way of doing it.
>> --
>> Posted viahttp://www.ruby-forum.com/.
>
> irb(main):001:0> a =3D 2,3,5,8
> =3D> [2, 3, 5, 8]
> irb(main):002:0> a.map!{|n| n*10 }
> =3D> [20, 30, 50, 80]
> irb(main):003:0> a
> =3D> [20, 30, 50, 80]

That's a little different, since it leaves you without the original
array (which may in fact be OK, but is an important difference).


David

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