From: Trick Nick <bornemann1@...>
Date: 2008-10-03T17:09:39+09:00
Subject: Re: Reg. Expressions with file directories

Here is my solution to my problem, just thought I would share just 
incase someone else runs into a similar problem or is having similar 
issues.

#first require the file utils, then take argument 1 or ARGV[0] and do a 
Dir.new ...to work on the given directory.  Then get the entries(files) 
to test to see  ...if they match the patterns given in the command line.
require 'fileutils'
givenDirectory = Dir.new("#{ARGV[0]}")
dirEntries = givenDirectory.entries.sort
i = 0

#Go through each file, or dirEntry and see if that file matches the 
pattern     ...given.
dirEntries.each do |file|
    if file.include?("#{ARGV[1]}") == true
#store the new file's name by using the gsub in order to replace the 
given      ...pattern(ARGV[1]) with the desired pattern from the 
commandline, or ARGV[2]
       newFileName = dirEntries[i].gsub("#{ARGV[1]}", "#{ARGV[2]}")
#using the new file name copy the orginal file, with the new file name.
       FileUtils.cp("#{ARGV[0]}\/#{file}", "#{ARGV[0]}\/#{newFileName}")
#rm the old file.
       print "File:#{file} \>\> NewFile:#{newFileName} \n"
       FileUtils.rm("#{ARGV[0]}\/#{file}")
       else
       print "#{file} DIDN'T CHANGE.\n"
   end
    i += 1
end
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