From: Nick Bo <bornemann1@...>
Date: 2008-09-29T06:52:53+09:00
Subject: Counting Tabs and splitting by that number

Basically i have a document which I am opening and then i am reading
each line of the file and having to split it up into two arrays and then
into a hash in which i have to get some sort of output like this:

application/activemessage has no extensions
application/andrew-inset has extensions ez
application/applefile has no extensions
application/atom has extensions atom
application/atomcat+xml has extensions atomcat
application/atomicmail has no extensions
application/atomserv+xml has extensions atomsrv
application/batch-SMTP has no extensions
application/beep+xml has no extensions
application/cals-1840 has no extensions

I have determined that if there are no tabs in the document then the
file has no extension so what i did was an if statement in the beginning
to see if the line contained the tab if not then it would save false to
the position in the array that i was at in the each loop.

file.each_line do |line|
        next if line[0] == ?#
        next if line == "\n"
        string = line
        if string.include?("\t") == false
            mimeValue[i] = false
            mimeKey[i]=string.split
        else

#THIS IS WHERE MY ISSUE IS NOW
mimeKey[i], mimeValue[i] = string.split("\t\t\t")
        end

My problem now that sometimes teh document is split by tabs changing in
number one line may have 3 tabs other may have 5 and one might just have
just 1.  So I am in a rut now How do i determine how many tabs are in
the line(string variable) thus so i can split the two parts into their
appropriate arrays.   I was thinking I could do some kind of recurssion
which would test to see if tab and if so then add 1 to count and then be
able to do something like

mimeKey[i], mimeValue[i] = string.split(#{tabCount}*("\t"))

I know there is alot in my message so here is a summary:

HOW TO COUNT \t IN A STRING THEN SPLIT BY THAT NUMBER OF \t
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