From: Daniel Moore <yahivin@...>
Date: 2008-09-20T11:14:53+09:00
Subject: Re: [QUIZ] One-Liners Mashup (#177 again)

It splats an array into it's components:
http://theplana.wordpress.com/2007/03/03/ruby-idioms-the-splat-operator/
. I couldn't use flatten because it would destroy nested arrays.

[[1,2],[3,4]].repeat(2) => [1, 2, 1, 2, 3, 4, 3, 4] #With flatten

[[1,2],[3,4]].repeat(2) => [[1, 2], [1, 2], [3, 4], [3, 4]] #Without flatten

On Fri, Sep 19, 2008 at 6:53 PM, Patrick Doyle <wpdster@gmail.com> wrote:
> On Fri, Sep 19, 2008 at 9:21 PM, Daniel Moore <yahivin@gmail.com> wrote:
>> def repeat(i)
>>  r = []; each { |x| r.push(*([x] * i)) }; r
>> end
>>
> Here's mine:
> def repeat(i)
>  self.map {|x| [x] * i}.flatten
> end
>
> I don't appreciate Ruby syntax enough to understand the significance
> of the *(...) construct in Daniel's solution.  What does that do?  Can
> you show an example where the results are different than my solution?
>
> --wpd
>
>



-- 
-Daniel
http://strd6.com