From: "DanDiebolt.exe" Date: 2008-09-12T03:08:14+09:00 Subject: Re: delete row in array of arrays --0-2126651997-1221156894=:42126 Content-Type: text/plain; charset=us-ascii Two successive delete_at methods will do what you ask with the c array modified: c=[[], [], ["BRKR", "2008-09-09, 11:08:28", "ISLAND", "-200","16.1000", "3,220.00", "-1.00", "3,446.688", "-1.0704", "0.00", ""],[]] c.delete_at(0) c.delete_at(0) c Perhaps you can get the essential info you need to manipulate with this: c.delete([]) c.flatten! I am not precisely sure why, but you cannot successfully chain either of the these two statements: c.delete_at(0).delete_at(0) c.delete([]).flatten! --0-2126651997-1221156894=:42126--