From: "Victor H. Goff III" <keeperotphones@...>
Date: 2008-09-08T02:29:00+09:00
Subject: Re: I have been looking at this little anomoly ?A => 65

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Thank you.  I did understand that the ?letter was actually taking the 'l'
and would have worked on it, as it should (had it not been for the 'etter'
directly afterward.  I just was trying to find out how to send ? something
in an iterator.  Bottom line: There are better ways to accomplish this.
(Oops, on the lack of hi.split(//) or .split(/./) )  I understand that, and
didn't catch it as I was writing the IRB of something I knew was going to
fail.

It was just something I came across, and hadn't seen it used in anything, so
was wondering the uses.





On Sun, Sep 7, 2008 at 12:15 PM, Thomas B. <tpreal@gmail.com> wrote:

> Victor Goff wrote:
> >>> hi.each {|letter| puts ?letter }
>
> You're trying something completely wrong here. The ? is only a compiler
> thing and not an operator. If you write ?letter, it's wrong because ?l
> can be interpreted as the code of the letter l, and the remaining etter
> is rubbish. It is not a real operator!
>
> Apart from that, your each doesn't split the string into letters, but
> into lines.
>
> In Ruby 1.8 if you want the code of n-th character of your str, just
> write str[n]. It doesn't return a single character, but its code.
>
> In Ruby 1.9 str[n] returns n-th character in the form of a short string,
> and to get code of n-th letter, write str[n].ord.
>
> TPR.
> --
> Posted via http://www.ruby-forum.com/.
>
>

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