From: Dave Goodchild <buddhamagnet@...>
Date: 2008-08-30T06:20:54+09:00
Subject: Re: Writing a method to handle a code block?

------=_Part_23398_1222080.1220045146786
Content-Type: text/plain; charset=ISO-8859-1
Content-Transfer-Encoding: 7bit
Content-Disposition: inline

As far as I understand it, passing a parameter to a method prefixed with &,
or the return value of 'lambda', creates or passes in
a Proc object which can continue to be called after the original function
call has gone out of scope i.e. a closure.

Yield by contrast is a way of communicating with a code block inside a
method, and the block can talk back. More useful
in iterations, transactions and so on.

On Fri, Aug 29, 2008 at 10:14 PM, Brian Ross <p.brian.ross@gmail.com> wrote:

> Thank you, everyone. If I understand correctly:
>
> &foo just means that whatever is passed to it (& requires a code block)
> will
> be saved as a local variable that may be used later.
>
> The call method executes the block that it acts on and then executes it but
> first assigns ttiuohe block's | block argument | to the parameter passed to
> it.
>
> Is it then that yield functions the same as the call method? I haven't
> quite
> gotten to proc objects yet, but it looks like using & converts the code
> block into an object, but yield, strictly, doesn't? Are code blocks the
> exception to the "everything in ruby is an object" rule?
>
> I'm certainly understanding this far better than I was previously, I think.
>
> Brian
>

------=_Part_23398_1222080.1220045146786--