From: Joel VanderWerf <vjoel@...>
Date: 2008-08-24T10:17:47+09:00
Subject: Re: How to create a block consisting of multiple lines.

Raj Singh wrote:
> This works.
> 
> class Person
>   def hi(inputproc)
>      inputproc.call
>   end
> end
> 
> Person.new.hi lambda { puts 'wow1'; puts 'wow2'}
> 
> However when I try to split the code inside block in multiple line the
> code does NOT work anymore.
> 
> This does NOT work.
> 
> class Person
>   def hi(inputproc)
>      inputproc.call
>   end
> end
> 
> Person.new.hi lambda do
>   puts 'wow1'
>   puts 'wow2'
> end
> 
> 
> How do I create a proc consisting of multiple lines of code.

do..end and {..} have different precedence. Your multiline example 
should work of you use {..} instead.

Or you can force precedence with (..).

What's going on with:

 > Person.new.hi lambda do
 >   puts 'wow1'
 >   puts 'wow2'
 > end

is that lambda is interpreted as the first param to #hi, and the do..end 
block is passed as a block to #hi (rather than to #lambda).

HTH.

-- 
       vjoel : Joel VanderWerf : path berkeley edu : 510 665 3407