From: "Pål Bergström" <pal@...>
Date: 2008-08-20T14:34:38+09:00
Subject: Re: Cut a string if length > n

Robert Klemme wrote:

> Pal, it seems we haven't seen the complete specification of what you
> want to do.  It seems that not only length is a condition but also
> positions of spaces.
> 
> I get the feeling that a solution using regular expressions might be
> more efficient and also easier in your case.  Maybe any of
> 
> str.sub! %r{\A(.{50}).*\z}, '\\1'
> str.sub! %r{\A(.{1,50})(?: .*)?\z}, '\\1'
> str.sub! %r{\s\S*\z}, ''
> 
> Depends on your string contents of course.
> 
> Kind regards
> 
>   robert

Hi. My app shows data in a list from a table called messages but only a 
fragment of it if it's to long.

My solution seems to work fine. What do you think of it? Will it always 
work?

lastspace = message.message[0..70].rindex(" ")
puts message.message[0..lastspace.to_i]

It doesn't do anything for non existing messages and text that isn't 
that long as 70. And it finds the last space. We might have long words 
in Swedish, but not that long :-) There will always be a space somewhere 
in the end where it can cut it without cutting and leave strange 
question marks as it cuts a swedish character (as Latin1 I guess).
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